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Conducting loops rotating through a half-plane magnetic field: the induced current of each loop matched to its graph
JEE Advanced 2026
Paper 1 · Question 15
Physics
Loops rotating through a half-plane field - the induced current follows the rate at which loop area crosses the field boundary
Moderate
Four loops turn clockwise about O with a field only for x > 0. The current follows how fast loop area crosses the field boundary: P constant then reversed (3), Q two pulses each way (2), R a pulse in and out (1), S zero because one lobe enters as the other leaves (4) - option C.
Open the interactive simulationSub-topics covered
- Faraday's law: emf = -dPhi/dt, with Phi = B x (area inside the field)
- A rotating sector's straight edge sweeps area at r^2 omega/2 while crossing the field boundary
- No crossing, no current: a loop wholly inside or outside the field
- Lenz's law and the sign of the current; lobes of one loop that circulate the same way
What it teaches
- Only the part of a loop inside x > 0 carries flux, so i ~ dA_in/dt
- P half-disc: area enters steadily for half a turn and leaves for the next: + constant then - constant (3)
- Q two sectors: + T/6 pulse, gap, + pulse, then - pulse, gap, - pulse (2); R one sector: a pulse in at the start and a pulse out after T/2 (1)
- S two opposite sectors: one crosses out as the other crosses in; both lobes circulate the same way, so the flux is constant and i = 0 (4); opposite senses would add, not cancel
- P3 Q2 R1 S4: option C
Simulation ID
- ADV-2026-P1-PHY-Q15 · revision 1
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