PRAYOGX
ADV-2026-P1-PHY-Q08

Plane-Wave Tracker — which way does E₀ sin(3y + 4z + ωt) travel?

JEE Advanced 2026 · Paper 1 · Physics · Q.8 · one or more correct options (+4 / partial / 0 / −1) · Electromagnetic waves

01The question

Q.8 The electric field associated with an electromagnetic wave travelling in vacuum is given by E0 sin(3y + 4z + ωt)î, where ω is the angular frequency. All quantities are in SI units. The correct statement(s) about this wave is/are:
[Given: speed of light in vacuum c = 3 × 108 ms−1.]
  1. (A)The wave is travelling in −(1/5)(3ĵ + 4k̂) direction.
  2. (B)The magnitude of the wave vector is 0.5 m−1.
  3. (C)The value of ω is 1.5 × 109 rad s−1.
  4. (D)The magnetic field associated with this wave is given by (E0/c) sin(3y + 4z + ωt)(4ĵ − 3k̂).

02The experiment

Answer— Press START: the tracker follows a crest, measures the wavelength, and finds B from Faraday's law.

Ready.

Show
Speed

03Detailed solution

Answer: —

  1. Read the wave vector. The phase is k·r + ωt with k = 3ĵ + 4k̂. So |k| = √(9 + 16) = 5 m⁻¹, and (B), which says 0.5 m⁻¹, is false. The wavelength is 2π/5 ≈ 1.257 m.
  2. Direction of travel. A crest keeps its phase: 3y + 4z + ωt = constant. As t grows, 3y + 4z must fall, so the wave moves against k, along −(3ĵ + 4k̂)/5. (A) is true. (With a "+ωt" phase, the wave travels opposite to k.)
  3. Frequency. In vacuum ω = c|k| = 3 × 10⁸ × 5 = 1.5 × 10⁹ rad/s, so (C) is true.
  4. Magnetic field (Faraday's law). ∂B/∂t = −∇ × E, and ∇ × (Ex î) = (∂Ex/∂z) ĵ − (∂Ex/∂y) k̂ = E₀ cos(…)(4ĵ − 3k̂). Integrating in time:
    B = (E₀/ω) sin(3y + 4z + ωt)(−4ĵ + 3k̂) = (E₀/c) sin(…) · (−4ĵ + 3k̂)/5.
    Option (D) has the opposite sign and is 5 times too large: its |B| would be 5E₀/c, not E₀/c. (D) is false. Check: E × B ∝ î × (−4ĵ + 3k̂) = −(3ĵ + 4k̂), along the direction of travel.

Understand the concept

For a plane wave sin(k·r ± ωt), the wavefronts are the planes k·r = constant. With "−ωt" they move along k; with "+ωt" they move against it. The size |k| = 2π/λ is fixed by the spatial part alone, and in vacuum ω = c|k|. The magnetic field is not a free choice. Faraday's law fixes it: it is perpendicular to both E and the direction of travel, has size E/c, and makes E × B point the way the wave goes.

Key takeaways

  • sin(k·r + ωt) travels along −k̂; sin(k·r − ωt) travels along +k̂.
  • |k| = √(kx² + ky² + kz²), λ = 2π/|k|, and ω = c|k|.
  • B = (1/c) n̂ × E, with |B| = |E|/c. Use a unit vector for n̂, and check that E × B points along n̂.

Verification: an independent derivation, a sympy route (Maxwell's equations applied to the given field), a numerical route (a crest followed through time and the curl found by finite differences), and the page's own engine, run by tests/verify_p1phyq08.py. The official key (A, C) and the MathonGo solution (A, C) agree. Status: script-verified by the PrayogX simulation factory; no review by a person has been recorded. The wave is shown in slow motion (the real period is 4.2 ns), and arrows are drawn to relative scale, with |B| shown as c|B|.

How to use this simulation

  1. Press ▶ START EXPERIMENT. The wavefronts (3y + 4z = constant) move across the y–z plane.
  2. Watch the tracker ride one crest. Its path gives the direction of travel, against the wave vector k.
  3. The ruler then measures the wavelength (so |k|), then ω = c|k|, then B from Faraday's law.
  4. Use Show to display E (out of the page, along x), B (in the plane), or both. The last stage checks options A to D.
  5. Replay runs it again. Reset clears it. Classroom fills the screen for a projector.