PRAYOGX Learn · Classes 9–12
Chapter 8 · Chemistry

Preparing Carboxylic Acids: Four Routes

Key points

  • Oxidation: RCH₂OH → RCHO → RCOOH with KMnO₄ or K₂Cr₂O₇; the carbon count stays the same.
  • Alkylbenzenes → benzoic acid with KMnO₄ (then H₃O⁺): the whole side chain becomes one COOH, if the carbon attached to the ring carries an H.
  • Hydrolysis: R–C≡N → amide → RCOOH; esters and acid chlorides also give acids.
  • RMgX + CO₂ (dry ice), then H₃O⁺ → RCOOH with one carbon more: the C–Mg bond pair attacks the carbon of CO₂.

The four routes

RouteStarting materialReagentProduct
Oxidation1° alcohol or aldehydeKMnO₄ or K₂Cr₂O₇ (acid)RCOOH (same C count)
Side-chain oxidationalkylbenzene (toluene)KMnO₄/OH⁻, then H₃O⁺benzoic acid
Hydrolysisnitrile, amide, ester, acid chlorideH₂O with H⁺ or OH⁻RCOOH
GrignardR–X → RMgXCO₂ (dry ice), then H₃O⁺RCOOH (one C more)

Grignard + CO₂, arrow by arrow

  • CH₃Br + Mg in dry ether → CH₃MgBr; its C–Mg bond is polar (C δ⁻).
  • The C–Mg bond pair attacks the carbon of CO₂ (new C–C bond); a C=O π pair moves onto O.
  • This gives CH₃COO⁻ ⁺MgBr; H₃O⁺ gives CH₃COOH: 1 C → 2 C.

Quick quiz

5 questions. Choose an answer for each, then submit to see your score and the explanations.

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